3x^2+10=7x^2-26

Solution for 3x^2+10=7x^2-26 equation:

3x^2+10=7x^2-26

We move all terms to the left:

3x^2+10-(7x^2-26)=0

We get rid of parentheses

3x^2-7x^2+26+10=0

We add all the numbers together, and all the variables

-4x^2+36=0

a = -4; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-4)·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-4}=\frac{-24}{-8}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-4}=\frac{24}{-8}
=-3
$